{"id":61,"date":"2022-01-19T07:04:50","date_gmt":"2022-01-18T22:04:50","guid":{"rendered":"https:\/\/chemical-engineering-review.com\/en\/?p=61"},"modified":"2022-01-19T07:06:45","modified_gmt":"2022-01-18T22:06:45","slug":"post-61","status":"publish","type":"post","link":"https:\/\/chemical-engineering-review.com\/en\/bernoullis-principle\/","title":{"rendered":"Bernoulli's principle\uff1aBasic formula for pump head calculation"},"content":{"rendered":"<h2>Outline<\/h2>\r\n<!-- \/wp:post-content -->\r\n\r\n<!-- wp:paragraph -->\r\n<p>The energy conservation law for fluids is called Bernoulli&#8217;s <span>principle<\/span> in particular.<\/p>\r\n<p>Bernoulli&#8217;s principle for a perfect fluid without compressibility and viscosity is expressed by Eq. (1).<\/p>\r\n<!-- \/wp:paragraph -->\r\n\r\n<!-- wp:paragraph {\"align\":\"center\"} -->\r\n<p style=\"text-align: center;\">$$\\frac{v_{2}^{2}-v_{1}^{2}}{2}+g(z_{2}-z_{1})+\\frac{P_{2}-P_{1}}{\u03c1}=0\u30fb\u30fb\u30fb(1)$$<\/p>\r\n<p>The first term represents kinetic energy, the second term represents potential energy, the third term represents pressure, and the energy of the fluid is the sum of these terms.<\/p>\r\n<p>It also means that kinetic energy and pressure can be converted into potential energy. This has very important industrial implications.<\/p>\r\n<p>Because it shows that you can lift a fluid to a higher level if you pump it to a higher pressure.<\/p>\r\n<p>Due to the location constraints, plants are often structured to be long and vertical structures.<\/p>\r\n<p>Equipment such as heat exchangers, distillation columns, and agitation vessels may be installed high up in the structure, so it is necessary to transport the fluid to them.<\/p>\r\n<p>Thanks to Bernoulli&#8217;s <span>principle<\/span>, engineers can calculate how much energy and pump lift is needed to lift a fluid to a given height.<\/p>\r\n<!-- \/wp:paragraph -->\r\n\r\n<!-- wp:paragraph {\"align\":\"center\"} \/-->\r\n\r\n<!-- wp:heading -->\r\n<h2>Derivation of Bernoulli&#8217;s Principle<\/h2>\r\n<p><img decoding=\"async\" src=\"https:\/\/chemical-engineering-review.com\/en\/wp-content\/uploads\/sites\/2\/2022\/01\/bernoullis-principle1.png\" alt=\"\" width=\"791\" height=\"406\" class=\"alignnone size-full wp-image-72 aligncenter\" srcset=\"https:\/\/chemical-engineering-review.com\/en\/wp-content\/uploads\/sites\/2\/2022\/01\/bernoullis-principle1.png 791w, https:\/\/chemical-engineering-review.com\/en\/wp-content\/uploads\/sites\/2\/2022\/01\/bernoullis-principle1-300x154.png 300w, https:\/\/chemical-engineering-review.com\/en\/wp-content\/uploads\/sites\/2\/2022\/01\/bernoullis-principle1-768x394.png 768w\" sizes=\"(max-width: 791px) 100vw, 791px\" \/><\/p>\r\n<p>We take the energy balance of the flow in the flow pipe as shown in the above figure.<\/p>\r\n<p>Assuming that the fluid is a perfect fluid, the energy loss associated with the flow can be neglected.<\/p>\r\n<p>Here, we consider each energy (kinetic energy, potential energy, and pressure) at the inlet and outlet of the flow pipe.<\/p>\r\n<p>In the physics of rigid bodies, each energy is Eq. (2)-(4).<\/p>\r\n<p class=\"has-text-align-center\" style=\"text-align: center;\">$$Kinetic\\ Energy=\\frac{1}{2}mv^{2}\u30fb\u30fb\u30fb(2)$$<\/p>\r\n<p style=\"text-align: center;\"><!-- \/wp:heading -->\r\n\r\n<!-- wp:paragraph {\"align\":\"center\"} --><\/p>\r\n<p class=\"has-text-align-center\" style=\"text-align: center;\">$$Potential\\ Energy=mgz\u30fb\u30fb\u30fb(3)$$<\/p>\r\n<p style=\"text-align: center;\"><!-- \/wp:paragraph -->\r\n\r\n<!-- wp:paragraph {\"align\":\"center\"} --><\/p>\r\n<p class=\"has-text-align-center\" style=\"text-align: center;\">$$Work\\ by\\ pressure (force\\ \u30fb\\ distance)=PA\u30fbx\u30fb\u30fb\u30fb(4)$$<\/p>\r\n<p>where <em>m<\/em> is the mass of a substance, <em>v<\/em> is the velocity of a substance, <em>g<\/em> is the <span>gravitational acceleration, <em>z<\/em> is location of a substance, <em>P<\/em> is pressure, <em>A<\/em> is Area where the force acts, <em>x<\/em> is travel distance.<\/span><\/p>\r\n<p>The units of each equation are kg\u30fbm2\/s2 = N\u30fbm = J (Joule).<\/p>\r\n<p>Basically, if we apply Eq. (2) to (4) to the fluid and take the energy balance at the inlet and outlet, we get the form of Bernoulli&#8217;s principle.<\/p>\r\n<p>First of all, the mass of the fluid is expressed by the following equation.<\/p>\r\n<p style=\"text-align: center;\">$$\u03c1Fdt$$<\/p>\r\n<p>where <em>\u03c1<\/em> is the fluid density, <em>F<\/em> is the volume flow rate , and <em>dt<\/em> is the fluid flow time in a very short time.<\/p>\r\n<p>The volume flow rate <em>F<\/em> can be expressed as the cross-sectional area of the section <em>A<\/em> and the flow velocity <em>v<\/em>.<\/p>\r\n<p style=\"text-align: center;\">$$F=Av$$<\/p>\r\n<p>The distance <em>x<\/em> traveled by the fluid is given by the flow velocity <em>v<\/em> and the time <em>dt<\/em> of fluid flow.<\/p>\r\n<p style=\"text-align: center;\">$$x=vdt$$<\/p>\r\n<p>Based on the above relationship, if the energy at the inlet of the flow pipe and the energy at the outlet are conserved and equal, then Eq. (5) holds.<\/p>\r\n<p><img decoding=\"async\" src=\"https:\/\/chemical-engineering-review.com\/en\/wp-content\/uploads\/sites\/2\/2022\/01\/bernoullis-principle1.png\" alt=\"\" width=\"791\" height=\"406\" class=\"alignnone size-full wp-image-72 aligncenter\" srcset=\"https:\/\/chemical-engineering-review.com\/en\/wp-content\/uploads\/sites\/2\/2022\/01\/bernoullis-principle1.png 791w, https:\/\/chemical-engineering-review.com\/en\/wp-content\/uploads\/sites\/2\/2022\/01\/bernoullis-principle1-300x154.png 300w, https:\/\/chemical-engineering-review.com\/en\/wp-content\/uploads\/sites\/2\/2022\/01\/bernoullis-principle1-768x394.png 768w\" sizes=\"(max-width: 791px) 100vw, 791px\" \/><\/p>\r\n<p style=\"text-align: center;\">$$\\begin{align}&amp;\\frac{1}{2}\u03c1F_{1}dtv_{1}^{2}+\u03c1F_{1}dt\u30fbg\u30fbz_{1}+P_{1}A_{1}\u30fbv_{1}dt\\\\&amp;=\\frac{1}{2}\u03c1F_{2}dtv_{2}^{2}+\u03c1F_{2}dt\u30fbg\u30fbz_{2}+P_{2}A_{2}\u30fbv_{2}dt\u30fb\u30fb\u30fb(5)\\end{align}$$<\/p>\r\n<p>The left side at Eq.(5) shows the energy at the inlet of the flow pipe and the right side shows the energy at the outlet of the flow pipe.<\/p>\r\n<p>Assuming that the fluid is always flowing continuously, Eq. (6) holds because the volume flow rate <em>F<\/em> is equal at all locations.<\/p>\r\n<p style=\"text-align: center;\">$$F_{1}=F_{2}=v_{1}A_{1}=v_{2}A_{2}\u30fb\u30fb\u30fb(6)$$<\/p>\r\n<p>Converting the volume flow rate <em>F<\/em> in Eq. (5) to <em>v<sub>1<\/sub>A<sub>1<\/sub><\/em> in Eq. (6) and dividing both sides of Eq. (5) by <em>\u03c1v<sub>1<\/sub>A<sub>1<\/sub>dt<\/em>, Eq. (7) is formed.<\/p>\r\n<p>$$\\begin{align}&amp;\\frac{1}{2}v_{1}^{2}+gz_{1}+\\frac{P_{1}}{\u03c1}\\\\&amp;=\\frac{1}{2}v_{2}^{2}+gz_{2}+\\frac{P_{2}}{\u03c1}\u30fb\u30fb\u30fb(7)\\end{align}$$<\/p>\r\n<p>If we put the form right side &#8211; left side = 0, we get Eq. (1), and Bernoulli&#8217;s principle can be derived.<\/p>\r\n<p style=\"text-align: center;\">$$\\frac{v_{2}^{2}-v_{1}^{2}}{2}+g(z_{2}-z_{1})+\\frac{P_{2}-P_{1}}{\u03c1}=0\u30fb\u30fb\u30fb(1)$$<\/p>\r\n<p>By the way, if you divide both sides of Eq. (7) by the gravitational acceleration <em>g<\/em>, the unit system of the equation becomes <em>m<\/em> (meter).<\/p>\r\n<p style=\"text-align: center;\">$$\\frac{v_{1}^{2}}{2g}+z_{1}+\\frac{P_{1}}{\u03c1g}=\\frac{v_{2}^{2}}{2g}+z_{2}+\\frac{P_{2}}{\u03c1g}$$<\/p>\r\n<p>In this case, the total energy hydraulic head <em>H<\/em>\u00a0is expressed by Eq. (8).<\/p>\r\n<p style=\"text-align: center;\">$$H=\\frac{v^{2}}{2g}+z+\\frac{P}{\u03c1g}=constant\u30fb\u30fb\u30fb(8)$$<\/p>\r\n<p>Eq. (8) is the base equation when calculating the pump head.<\/p>\r\n<p>Each term in the equation is referred to as<\/p>\r\n<p class=\"has-text-align-center\" style=\"text-align: center;\">$$Velocity\\ Head\uff1a\\frac{v^{2}}{2g}$$<\/p>\r\n<p style=\"text-align: center;\"><!-- \/wp:paragraph -->\r\n\r\n<!-- wp:paragraph {\"align\":\"center\"} --><\/p>\r\n<p class=\"has-text-align-center\" style=\"text-align: center;\">$$Positional\\ Head\uff1az$$<\/p>\r\n<p style=\"text-align: center;\"><!-- \/wp:paragraph -->\r\n\r\n<!-- wp:paragraph {\"align\":\"center\"} --><\/p>\r\n<p class=\"has-text-align-center\" style=\"text-align: center;\">$$Pressure\\ Head\uff1a\\frac{P}{\u03c1g}$$<\/p>\r\n<!-- \/wp:paragraph -->\r\n\r\n<!-- wp:paragraph \/-->\r\n\r\n<!-- wp:image {\"align\":\"center\",\"id\":1148,\"sizeSlug\":\"large\"} \/-->\r\n\r\n<!-- wp:paragraph -->\r\n<h2>Extension to real viscous fluids<\/h2>\r\n<p>Eq. (1) and (8) are valid for perfect fluids, which are fluids in which viscosity does not work.<\/p>\r\n<p>However, because of the viscous nature of real world fluids, energy loss due to friction, etc. occurs.<\/p>\r\n<p>So, in order to apply Eq. (8) to a real fluid, we add two terms to Eq. (8) to represent the energy loss.<\/p>\r\n<p style=\"text-align: center;\">$$H=\\frac{v^{2}}{2g}+z+\\frac{P}{\u03c1g}+h_{f}+h_{l}\u30fb\u30fb\u30fb(9)$$<\/p>\r\n<p>Eq. (9) is used in practice to calculate the pump head.<\/p>\r\n<p>The <em>h<sub>f<\/sub><\/em> is called the frictional loss hydraulic head and represents the energy loss due to friction on the pipe wall.<\/p>\r\n<p>The <em>h<sub>l<\/sub><\/em> is called the shape loss hydraulic head, and it represents the energy loss that occurs at points where the flow path changes significantly, such as at a sudden expansion or contraction of the pipe or at a bend.<\/p>\r\n<p>Therefore, when calculating the head of the pump, it is necessary to determine the head by adding the energy loss according to Eq. (9).<\/p>","protected":false},"excerpt":{"rendered":"<p>The energy conservation law for fluids is called Bernoulli&#8217;s principle in particular. Thanks to Bernoulli&#8217;s principle, engineers can calculate how much energy and pump lift is needed to lift a fluid to a given height.<\/p>\n","protected":false},"author":1,"featured_media":71,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[7],"tags":[],"class_list":["post-61","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-fluid-dynamics"],"_links":{"self":[{"href":"https:\/\/chemical-engineering-review.com\/en\/wp-json\/wp\/v2\/posts\/61","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/chemical-engineering-review.com\/en\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/chemical-engineering-review.com\/en\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/chemical-engineering-review.com\/en\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/chemical-engineering-review.com\/en\/wp-json\/wp\/v2\/comments?post=61"}],"version-history":[{"count":13,"href":"https:\/\/chemical-engineering-review.com\/en\/wp-json\/wp\/v2\/posts\/61\/revisions"}],"predecessor-version":[{"id":77,"href":"https:\/\/chemical-engineering-review.com\/en\/wp-json\/wp\/v2\/posts\/61\/revisions\/77"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/chemical-engineering-review.com\/en\/wp-json\/wp\/v2\/media\/71"}],"wp:attachment":[{"href":"https:\/\/chemical-engineering-review.com\/en\/wp-json\/wp\/v2\/media?parent=61"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/chemical-engineering-review.com\/en\/wp-json\/wp\/v2\/categories?post=61"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/chemical-engineering-review.com\/en\/wp-json\/wp\/v2\/tags?post=61"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}